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Intious calculated answer

4 × 10h shifts: 2 posts, 0% unavailable

One ten-hour service window on each of four days.

Your result

Same scenario, three explicit full-time baselines
Full-time h/weekAvailable h/personRequired FTEWhole people
35352.293
37.537.52.133
404022

80 required coverage hours/week. At 40h full-time, rounding to 2 people leaves 0 aggregate hours of capacity; those hours may not fall when coverage is needed.

Worked example: 4 × 10h shifts: 2 posts, 0% unavailable

4 shifts × 10 hours × 2 concurrent posts = 80 coverage hours/week. Each 40h employee contributes 40 × (1 − 0/100) = 40 available hours. 80 ÷ 40 = 2 FTE, rounded up to 2 whole people.

A small pool can have enough total hours yet still fail weekend or concentrated-day availability. Match individual availability to each service window. Both posts need to be filled at the same time; one person cannot fill both simultaneously.

Assumptions and limits

  • Shifts/week is per post; hours/shift means required coverage time, not necessarily paid hours.
  • Unavailability is an assumed share of contracted hours lost to leave, training or other duties. Do not deduct the same absence twice.
  • People are rounded up only after dividing total hours by available capacity. Role matching, handovers, rest and break relief need a separate roster check.
  • No payroll, overtime or legal compliance guarantee is made.

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Related guides: Workforce and FTE guides