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Intious calculated answer

5 × 6h shifts: 2 posts, 0% unavailable

One six-hour service window on each of five weekdays.

Your result

Same scenario, three explicit full-time baselines
Full-time h/weekAvailable h/personRequired FTEWhole people
35351.712
37.537.51.62
40401.52

60 required coverage hours/week. At 40h full-time, rounding to 2 people leaves 20 aggregate hours of capacity; those hours may not fall when coverage is needed.

Worked example: 5 × 6h shifts: 2 posts, 0% unavailable

5 shifts × 6 hours × 2 concurrent posts = 60 coverage hours/week. Each 40h employee contributes 40 × (1 − 0/100) = 40 available hours. 60 ÷ 40 = 1.5 FTE, rounded up to 2 whole people.

Assign individual people to the stated windows and check overlaps. A total-hours result alone cannot guarantee coverage at each moment. Both posts need to be filled at the same time; one person cannot fill both simultaneously.

Assumptions and limits

  • Shifts/week is per post; hours/shift means required coverage time, not necessarily paid hours.
  • Unavailability is an assumed share of contracted hours lost to leave, training or other duties. Do not deduct the same absence twice.
  • People are rounded up only after dividing total hours by available capacity. Role matching, handovers, rest and break relief need a separate roster check.
  • No payroll, overtime or legal compliance guarantee is made.

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Shift Coverage Calculator · All free calculators · Calculation methodology

Related guides: Workforce and FTE guides