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Intious calculated answer

4 × 8h shifts: 1 post, 20% unavailable

Two eight-hour service windows on each weekend day.

Your result

Same scenario, three explicit full-time baselines
Full-time h/weekAvailable h/personRequired FTEWhole people
35281.142
37.5301.072
403211

32 required coverage hours/week. At 40h full-time, rounding to 1 people leaves 0 aggregate hours of capacity; those hours may not fall when coverage is needed.

Worked example: 4 × 8h shifts: 1 post, 20% unavailable

4 shifts × 8 hours × 1 concurrent post = 32 coverage hours/week. Each 40h employee contributes 40 × (1 − 20/100) = 32 available hours. 32 ÷ 32 = 1 FTE, rounded up to 1 whole people.

A small pool can have enough total hours yet still fail weekend or concentrated-day availability. Match individual availability to each service window. This example covers one concurrent post, not every role in a department.

Assumptions and limits

  • Shifts/week is per post; hours/shift means required coverage time, not necessarily paid hours.
  • Unavailability is an assumed share of contracted hours lost to leave, training or other duties. Do not deduct the same absence twice.
  • People are rounded up only after dividing total hours by available capacity. Role matching, handovers, rest and break relief need a separate roster check.
  • No payroll, overtime or legal compliance guarantee is made.

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Related guides: Workforce and FTE guides